Wednesday, May 3, 2023

Find The Indicated Probability Using The Standard Normal Distribution


Find The Indicated Probability Using The Standard Normal Distribution

If z is a standard normal variable, find the probability that z lies between -1.10 and -0.36 !

Daftar Isi

1. If z is a standard normal variable, find the probability that z lies between -1.10 and -0.36 !


Jawaban:

YNTKTS :((((((((((((((((


2. What is the effect on the amount of safety stock provided by the stochastic continuous-review model presented in Sec. 19.5 when the following change is made in the inventory system. (Con- sider each change independently.) (a) The lead time is reduced to 0 (instantaneous delivery). (b) The service level (measure 1) is decreased. (c) The unit shortage cost is doubled. (d) The mean of the probability distribution of demand during the lead time is increased (with no other change to the distribu- tion). (e) The probability distribution of demand during the lead time is a uniform distribution from a to b, but now (ba) has been doubled. (f) The probability distribution of demand during the lead time is a normal distribution with mean μ and standard deviation σ, but now σ has been doubled.


Jawab:

(a) If the lead time is reduced to 0, the amount of safety stock would be reduced because there is no longer a need to account for the time it takes to receive a new shipment.

(b) If the service level (measure 1) is decreased, the amount of safety stock would be increased because a lower service level means a higher risk of stockouts, and therefore, a greater need for safety stock.

(c) If the unit shortage cost is doubled, the amount of safety stock would be increased because a higher cost of stockouts means that there is a greater need to avoid them, and therefore, a greater need for safety stock.

(d) If the mean of the probability distribution of demand during the lead time is increased, the amount of safety stock would be increased because a higher mean demand means a higher likelihood of stockouts, and therefore, a greater need for safety stock.

(e) If (ba) is doubled, the amount of safety stock would be increased because a wider range of possible demand means a higher risk of stockouts, and therefore, a greater need for safety stock.

(f) If σ is doubled, the amount of safety stock would be increased because a larger standard deviation means a higher risk of stockouts, and therefore, a greater need for safety stock.

Penjelasan dengan langkah-langkah:


3. Table 2 below represents the probability distribution of discrete random variable X.P(X=r)Table 2Find the value of k.(3 Marks)Y is a continuous random variable with probability density functionJy? .-22Find the expected value of h.(2 Marks)25. find m​


Jawaban:

meja tenis meja yg kecil


4. The probability distribution of a less risky return is more peaked than that of a riskier return. What shape would the probability distribution have for (a) completely certain returns and (b) completely uncertain returns?


Jawaban:

Distribusi probabilitas pengembalian yang kurang berisiko lebih memuncak daripada

pengembalian yang lebih berisiko. Bagaimana bentuk distribusi probabilitas untuk (a)

pengembalian yang benar-benar pasti dan (b) selesai

Penjelasan:

B.


5. a letter is selected at random from each of the word 'NICE' and 'ICE' represent the sample space using a possibility diagram and find the probability two letters are the same and the vowels!​


Jawaban:

Correct options are A) , B) and C)

(A) Total number of letters in the given word = 4, out of these O and E are two vowels.

Let S be the sample space, then

S={HO,HM,HE,OM,OE,ME}⇒n(S)=6

Let A1 be the event of taking two vowels, then 

A1={OE}=n(S)n(A1)=61

(B) Let A2 be the event of taking at least one vowel, then we have

A2={HO,HE,OE,ME,MO}⇒n(A2)=5

Hence, required probability =n(S)(n(A2))=65

(C) Let A3 be the event of taking one letter as M, then we have A3={HM,OM,ME}⇒n(A2)=5

Hence,required probability =n(S)n(A3)=63=21

Penjelasan dengan langkah-langkah:

maaf kalau ada slah


6. The figure is formed using 4 semicircle. Find the perimeter of the shaded part


nilai keliling dan luas lingkaran dari :

21 cm : keliling dan luas lingkaran adalah 132 cm dan 1386 cm².

21 cm : keliling dan luas lingkaran adalah 66 cm dan 346,5 cm².

21 cm : keliling dan luas lingkaran adalah 75,36 cm dan 452,16 cm².


7. A die is rolled, find the probability that an even number is obtained


Ruang sampel = {1,2,3,4,5,6}
n(S) = 6
Sampel bagian = {2,4,6}
n(B) = 3

Peluang = 3/6 = 1/2

Semoga membantu, maaf kalau salah

8. Find the synonym of the following words by using the colored lines


Jawaban:

1. Avoided        = Evaded

2. Cluster         = Group

3. Commercial = Profitable

4. Common      = Usual

5. Consume     = Eat up

6. Pregnant      = Expecting

7. Remedies    =  Cures

8. Herbs          = Plants

9. Traditionaly = Conventionally

10. Surface      =  Exsternal

Penjelasan:

Arti

1. Dihindari

2. Grup, Kelompok

3. Menguntungkan

4. Umum, biasa

5. Konsumsi

6. Hamil

7. Obat

8. Tanaman

9. Tradisional, konvensional

10. Permukaan, bagian luar

Pelajari lebih lanjut tentang sinonim di https://brainly.co.id/tugas/3602265

#BelajarBersamaBrainly


9. John is playing a chess game against Peter. If the probability that John will win is 4/7 and the probability that Peter will win is 1/7 , find the probability that the chess game will end in a draw.


John probability + Peter probability

= 4/7 + 1/7 = 5/7

Draw probability

= 7/7 - 5/7 = 2/7

So the probability that the chess will end in a draw is 2/7


10. Sixty percent of children in a school do not have cavities. Let x be the number of children in a random sample of 20 children selected from this school who do not have cavities. The standard deviation of the probability distribution of x is approximately: ?


Jawaban:

Let X Be The Number Of Children In A Random Sample Of 50 Children Selected From This School Who Do Not Have Cavities. The Mean ... ·


11. a standard pack of 52 playing cards is randomly divided into two unequal piles. Given that the probability of drawing a picture card from the smaller pile is 4/11 while the probability of drawing a non-picture card from the bigger pile is 13/15, find the number of cards in each pile


Jawaban:

52 kartu remi dibagi secara acak menjadi dua tumpukan yang tidak rata.Mengingat bawah probabilitas mengambar kartu gambar dari tumpukan yang lebih kecil adalah 4/11 dan probabilitas menggambar kartu nonfoto dari tumpukan yang lebih besar adalah 13/15 temukan jumlah kartu disetiap tumbukan


12. You have been given this probability distribution for the holding-period return for a stock !


Jawaban:

1. i am sorry we have not a stock again. please come back on 3 pm, beacause on 3 pm we have the stock

2. i am sorry we have not a stock again can you come back on 5 pm because on 5 pm we have again the stock


13. Two coins are tosses, find the probability that two heads are obtained


n(S) = 2^2
= 4

probability 2 headd obtained = 1/4

14. Find the number of moles of the indicated species: a) 333 mg of Na2B4O7.10H20


Jawaban:

Penjelasan:

[tex]\text{Na}_2\text{B}_4\text{O}_7.10\text{H}_2\text{O}[/tex]

Mr = 2Na + 4B + 8O + 20H

Mr = 2(23) + 4(11) + 17(16) + 20(1)

Mr = 46 + 44 + 272+ 20

Mr = 382

[tex]n = \frac{m}{Mm}\\n = \frac{333}{382}\\n = 0,87 \times 10^-3 \ \text{mol}[/tex]


15. read the look box. then write five personal predictions about the future of the planet,using will and the adverbs of probability​


Jawaban:

I don't know it's God's business


16. Find the synonym of the following word by using the colored lines​


Jawaban:

2. elvoved = developed

3. climate = weather

4. liquid = fluid

5. ingredients = elements

6. investigated = examined

7. originally = formerly

8. product = commodity

9. protect = defend

10. well-known = famous


17. For the function f, find the indicated limit or function value, or state that it dose not exist.​


Jawaban:

fuck .......................


18. two coins are tossed, find the probability that two heads are obtained


p(A)=n(A)/n(s)
n(A) =2 two heads
n(s)= 4 jumlah seluruh 
so , 
p(A)=2/4 =1/2 

19. The number of houses sold by an estate agent follows a Poisson distribution with a mean of 2 per week. Find the probability that in the next 4 weeks, the estate agent sells more than 6 houses. ​


Jawab:

An average of 2 per week means that the agent on average sells 8 houses per month (per 4 weeks). Therefore, we are going to compare the probability of the agent selling more than 6 houses per month given the average of 8 per month (λ = 8).

P(x = k) = λ^k × e^(-λ) ÷ k!

P(x = 0) = 8^0 × e^(-8) ÷ 0!

P(x = 1)  = 8^1 × e^(-8) ÷ 1!

P(x > 6) = 1 - P(x ≤ 6)

P(x > 6) = 1 - [P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)]

P(x > 6) = 1 -  P(x <= 6)

P(x > 6) = 1 - 0.31337

P(x > 6) = 0.68663


20. using the number line find the diffrence between -2 and 3​


Penjelasan dengan langkah-langkah:

pertama buat garis bilangan. trus dari titik nol, bergerak ke kiri menuju ke titik -2, kemudian bergerak 5 langkah kekanan menuju titik 3. jadi selisih antara -2 dengan 3 adalah 5


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