2. The equilibrium constant Kp for the reaction2SO3 +2SO2(g) + O2(g)is 1.8 x 10-5 at 350°C. What is Kc for this reaction?
1. 2. The equilibrium constant Kp for the reaction2SO3 +2SO2(g) + O2(g)is 1.8 x 10-5 at 350°C. What is Kc for this reaction?
Jawaban:
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2. The rate constant for a first-order reaction is 3.64. 10 - 2 seconds -1 at 298 k.. what is the rate constant for the reaction at 350 k if the activation energy of the reaction is 50.2 kj/mol. given: the quantity r = 8.314 j/k.mol.
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3. The equilibrium constant for the reactionCO(g) + H2O(g) <-> CO2(g) + H2(g) Is 25 at 600 K Degree. If 4 moles of CO(g) and H2O(g) each are reacted in the volumes 1 L, What are the composition of gases at equilibrium ?
CO(g) + H2O(g) <-> CO2(g) + H2(g) Keq = 25
let 2 side devided by 4
4CO(g) + 4H2O(g) <-> 4CO2(g) + 4H2(g)
So, Keq = 25⁴ = 390.625
4. Evaluate the equilibrium constant for N2O4(g) ↔ 2 NO2(g) at 298 K if ΔfG⁰ NO2 = 51,3 kJ/mol ΔfG⁰ N2O4 = 99,8 kJ/mol
Jawaban:
0,323
Penjelasan:
ΔrG⁰ = 2 × ΔfG⁰ NO2 – ΔfG⁰ N2O4
ΔrG⁰ = 2 × 51,3 kJ/mol – 99,8 kJ/mol
ΔrG⁰ = 102,6 kJ/mol – 99,8 kJ/mol
ΔrG⁰ = 2,8 kJ/mol
ΔrG⁰ = 2800 J/mol
[tex]lnK = \frac{-\Delta_rG^0}{RT}[/tex]
[tex]lnK=\frac{-2800J/mol}{(8,314J/molK)(298K)}[/tex]
[tex]lnK=-1,13[/tex]
[tex]K=0,323[/tex]
Jawaban:
0,323
maaf kalu salah
Penjelasan:
ΔrG0 = 2 × 51,3 kJ/mol – 99,8 kJ/mol
ΔrG0 = 102,6 kJ/mol – 99,8 kJ/mol
ΔrG0 = 2,8 kJ/mol
ln K = -(ΔrG0)/RT
ln K = -(2,8kJ/mol)/(8,314 J⁄(mol K )×298 K)
K = 0,323
5. Quicklime (CaO) is produced by the thermal decomposition of calcium carbonate (CaCO3). Calculate the volume of CO₂ at STP produced from the decomposition of 152 g CaCO, by the reaction
Penjelasan:
caco3 ----- cao + co2
mol cao =mol co2 = 152 / 56 = 2.7 mol
volume STP = mol x 22,4 L = 2,7 x 22,4 = 60,48 L
6. Write the mechanism of the following reaction CH3CH2OH + HBr ---->
substitution reaction
CH3-CH2-OH + HBr --> CH3 - CH2 - Br + H2O
I hope its helps...
7. Calculate the heat of reaction for combustion of C2H5OH using bond energies
Reaction C₂H₅OH + 3O₂ --> 2CO₂ + 3H₂O
Then draw the structural formulas for each molecule showing single and double bonds.
C₂H₅OH has one C-C bond, five C-H bonds, one C-O bond and one O-H bond
add up the bond energies for a mole of each of these single bonds from your bond energy chart.
Now in O₂ we have O=O double bond so add up the total bond energy for three moles of O₂. (three times the doubly bonded oxygen bond energy)
CO₂ is formed O=C=O, and you have two moles of CO₂, and four moles of C=O bonds so multiply the C=O bond energy by 4
and for H₂O, bonded H-O-H you will have 6 moles of H-O bonds, so multiply the H-O bond energy by six.
Now to get ΔH for this reaction, simply subtract the sum of the reactant bond energies from the sum of the product bond energies and you have it.
8. Find the equilibrium concentration of CO in the reactionco (g) + Clz (g)COCI2 (g)Kc=1.2 × 10^3 at 395°C
Jawaban:
semoga membantu,
Penjelasan:
awalnya,
samakan reaksinyalalu setelah koefisien disamakan, maka misalkan jika koefisien 1 disimbolkan x maka yang lain akan menyesuaikanlalu masukkan rumus nya9. balance the following redox reaction using half reactionC2O42- + MnO4-->MN2+ + CO2
Jawaban:
Frank Lampard ingin tahu bagaimana cara agar cepat punya anak dari seorang teman yang baik dan benar
10. Calculate the unknown in each of the following diagrams
Jawaban:
[tex]d = \sqrt{165} [/tex]
[tex]e = \sqrt{201} [/tex]
Penjelasan dengan langkah-langkah:
Step1:
d=√19²-14²
d=√361-196
d=√165
Step 2:
√(√165)²+6²=e
√165+36=e
√201=e
11. If the mass is found as following = Copper : 0,52g H2O : 0,245g Chloride : 23.872g Calculate the empirical formula of substance in the reaction.
gangerti kak aku juga bingung
12. tolong bantu kaawe use the bond......energy to calculate enthalpy of the reaction
of?
maaf kalo salah. ini materinya tentang apa ya kalo boleh tau? ada pilihannya ga?
13. what is the formula to calculate rate of reaction?
if you calculated for chemestry for reaction you must be know is formula of mole ,molaritas and valensi of ionic atom.
14. 2. The following data were collected for the reaction2NO + Cl2 -------> 2 NOClExp NO (M) Cl2(M) Rates (M/s)1 0,01 0,01 0,0062 0,01 0,02 0,0123 0,02 0,01 0,0244 0,03 0,05 ?a. Write the expression for the rate law. b. Calculate the value of rate constant
Jika suatu reaksi kimia berlangsung berdasarkan persamaan berikut :
2NO + Cl2 ⇒ 2NOCl
dan diperoleh data sebagai berikut :
NO (M) Cl2 (M) v (M/s)
0.01 0.01 0.006
0.01 0.02 0.0.12
0.02 0.01 0.024
Berasarkan data tersebut diperoleh persamaan laju reaksi :
v = k [NO]ᵃ[Cl2]ᵇ
exp 1 ⇒ 0.006 = k [0.01]ᵃ[0.01]ᵇ
exp 2⇒ 0.012 = k [0.01]ᵃ[0.02]ᵇ
exp 3⇒ 0.024 = k [0.02]ᵃ[0.01]ᵇ
dari pers (1) dan (2) diperoleh :
0.012/0.006 = [0.02/0.01]ᵇ
2 = [2]ᵇ
maka b = 1
dari pers (2) dan (3) diperoleh :
0.024/0.012 = [0.02/0.01]ᵃ[0.01/0.02]
2 = [2]ᵃ[1/2]
4 = [2]ᵃ
a = 2
maka persamaan laju reaksi dapat dituliskan dengan :
v = k [NO]²[Cl2]
berdasarkan persamaan (1) maka diperoleh nilai tetapan laju reaksi k adalah
v = k [NO]²[Cl2]
0.006 = k [0.01]²[0.01]
0.006 = 0.000001 k
k = 6000
PembahasanLaju reaksi merupakan laju pengurangan konsentrasi zat pereaktan per satuan waktu dalam suatu reaksi kimia. Dalam suatu reaksi, konsentrasi zat pereaktan akan berkurang, sedangkan konsentrasi produk akan bertambah. Reaksi akan berlangsung hingga tidak terjadi perubahan konsentrasi lagi. Pada kondisi tersebut reaksi dikatakan mencapai kesetimbangan.
Prinsip laju reaksi didasarkan pada teori tumbukan. Reaksi tumbukan menyatakan bahwa partikel-partikel reaktan bergerak bebas secara acak, partikel-partikel bertumbukan sehingga terjadi reaksi. Tumbukn efektif merupakan tumbukan antar partikel yang menghasilkan reaksi kimia. Jika suatu reaksi kimia dinyatakan dengan :
aA + B ⇒ cC
Maka laju reaksi di rumuskan dengan :
v = k [A]ᵃ[B]ᵇ
dimana k adalah konstanta laju reaksi, [A] dan [B] adalah konsentrasi reakan dan a dan b ditentukan berdasarkan percobaan.
Laju reaksi bergantung pada beberapa faktor diantaranya :
Konsentrasi reaktan, reaktan denga konsentrasi pekat akan bereaksi lebih cepat, sehingga laju reaksi meningkat.temperatur, partikel-partikel memiliki cukup energi untuk bergerak akibat adanya temperatur. sehingga semakin tinggi temperatur jumlah tumbukan energi lebih banyak. Hal ini mengakibatkan peningkatan laju reaksi.Bentuk fisik reaktan, reaktan erbentuk serbuk halus akan lebih cepat bereaksi dibandingan yang berbentuk bongkahan arena memiliki luas permukaan aktif lebih besarkatalis merupakan zat yang mampu membercepat reaksi. keberadaan katalis tidak menjadi kontaminasi pada produk.Pelajari lebih lanjutkonstanta laju reaksi di link brainly.co.id/tugas/16342075Orde reaksi di link brainly.co.id/tugas/13003076Kesetimbangan reaksi di link brainly.co.id/tugas/13433982Detail tambahanKelas : XI SMA
Mapel : Kimia
Materi : Laju Reaksi
Kode : 11.7.3
Kata Kunci : Laju reaksi, teori tumbukan, faktor laju reaksi.
15. tye certain value of water equilibrium constant (kw) at certain temperature and pressure is 2 × 10^14. the ph of 0,001 M Ba(OH)2 solution at the temperature is...
Gunakan cara biasa saja, tapi Kw diubah jadi 2 × 10^-14.
Ba(OH)2 adalah basa kuat yang DIASUMSIKAN terionisasi sempurna menurut reaksi:
Ba(OH)2(aq) --> Ba2+(aq) + 2 OH-(aq)
0.001 M
[OH-] = 2 × 0.001 = 2 × 10^-3 M
[H+] = Kw / [OH-]
[H+] = 2 × 10^-14 / (2 × 10^-3)
[H+] = 10^-11
pH = -log[H+] = 11
16. mohon bantuannyawhen 8.0 g of metal (M) was oxidized in the oxygen atmosphere 10 g of MO was obtained owing the following reaction. Answer the following questions2M + O₂ ⇒ 2MO1. How many liter of O₂ were needed in this reaction? answer the volume at the standard state2. Calculate the weight percentage of M in MO3. Calculate the atomic weight of M
2M + O₂ ⇒ 2MO
8 g 2 g 10 g
0,125 mol 0,0625 mol
1) O₂ Volume = [tex] \frac{gram}{Mr}.22,4 = \frac{2}{32}.22,4= 1,4 [/tex] liter
3) mol = [tex] \frac{gram}{Ar} [/tex]
0,125 = [tex] \frac{8}{Ar} [/tex]
Ar M = [tex] \frac{8}{0,125} = 64 [/tex]
2) percentage M in MO
[tex] \frac{Ar M}{Mr MO} [/tex] x 100%
[tex] \frac{64}{80} [/tex] x 100% = 80%
17. Among the following compounds, the most active electrophilic addition reaction is .....
Among the following compounds, the most active electrophilic addition reaction is .....
Jawaban:- Nuclear
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18. 3) 0.1 mol of lithium reacts with excess oxygen gas. (a) Write a balanced chemical equation for the reaction. (b) Calculate the mass of the product formed.
Jawaban:
Penjelasan:
(a) A balanced chemical equation for the reaction is:
2Li + O2 -> 2Li2O
(b) To calculate the mass of the product formed, we can use the molecular weight of lithium oxide (Li2O). The molecular weight of Li2O is 30.8 g/mol. Therefore, the mass of 0.1 mol Li2O is 3.08 grams.
19. Calculate the difference (selisih) between the volume of the following!
penyelesaian :
= p × l × t - p × l × t
= 3 × 3 × 6 - 2 × 3 × 2
= 54 - 12
= 42 cm³
Jawaban dan langkah langkah penyelesaian ada di dalam lampiran ya semoga membantu.
Jangan lupa apabila membantu jadikan jawaban tercerdas ya terimakasih ^_^
20. [1]15 Look at the following L-shape.8 cm12 cm6 cm15 cma) Calculate the area of the shape....cm? [1]b) Calculate the perimeter of the shape..cm [1]
Jawaban:
A
Penjelasan dengan langkah-langkah:
Mungkin benar saya kurang paham
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