apa manfaat potassium iodide???
1. apa manfaat potassium iodide???
menghalang idengan berkesan penyerapan iodin berradioaktif kedalam kelenjar tiroid manusia.
2. Potassium nitrate is used in
kaliium nitrab di gunakan untuk gigi sensitif
senyawa yang mengandung nitrogen yang secara kolektif mengacu pada saltpeter atau saltpetre.
potassium nitrab used for sensitive teeth nitrogen-containing compounds that collectively refers to the saltpeter or saltpetre .
terimakasih
thanks
Uses of potassium nitrate in agriculture, industry, solar energy plants, food and pharma.
3. afua mixes a solution of potassium iodide with a solution of lead nitrate.birth of the solutions are clear and colourless.the resulting mixture is cloudy and yellow.the yellow precipitate is lead iodide,one of the products on this reaction.what is the name of the other products
Jawaban:
Potassium nitrate KNO[tex]_{3}[/tex]
Penjelasan:
2KI + Pb(NO[tex]_{3}[/tex])[tex]_{2}[/tex] ------> 2KNO[tex]_{3}[/tex] + PbI[tex]_{2}[/tex]
Jawaban:
nowiwohuqlbbhuwongaonvvg
4. Question 2 40g of iron (III) oxide is reduced by carbon powder to form iron and carbon dioxide. (Relative atomic mass: 0 = 56, Fe = 56) (a) Write a balanced chemical equation for the reaction.
Iron (III) oxide = Fe2O3
Carbon = C
Iron = Fe
Carbon dioxide = CO2
Maka reaksi yang terjadi
Fe2O3 + C -> Fe + CO2
Untuk proses penyetaraan dapat dilakukan dengan metode langsung atau melalui setengah reaksi, berikut metode setengah reaksi dalam lingkungan asam.
Tuliskan masing-masing spesi yang mengalami oksidasi dan reduksi
Reduksi: Fe2O3 -> Fe
Oksidasi: C -> CO2
Selanjutnya ruas yang kekurangan atom O ditambah dengan H2O, ruas yang kelebihan atom H ditambah dengan H+ dan ruas yang muatannya belum setimbang ditambakan e (elektron) hingga muatan kedua ruas sama besar
Reduksi: Fe2O3 + 6H+ + 6e -> 2 Fe + 3 H2O x2
Oksidasi: C + 2 H2O -> CO2 + 4H+ + 4e x3
Sama kan koefisien e (elektron) masing-masing reaksi dengan mengalikan ekuivalen agar sama.
Reduksi: 2 Fe2O3 + 12H+ + 12e + 4 Fe + 6 H2O
Oksidasi: 3 C + 6 H2O -> 3 CO2 + 12H+ + 12e
Spesi yang sama pada kedua ruas dapat dihilangkan maka
Reaksi total; 2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
5. amonia nitrate is prepared commericially by passing ammonia gas through a solution of nitre acid . write down the balnce equation
[STOICHIOMETRY | X SHS]
Ammonium Nitrate : NH₄NO₃
Ammonia : NH₃
Nitrate acid : HNO₃
Reaction :
NH₃ + HNO₃ --> NH₄NO₃ (balanced)
6. word and balanced symbol equations for sodium hydroxide and hydrochloric acid
Jawaban:
- Natrium Hidroksida (NaOH)
- Asam Klorida (HCl)
Penjelasan:
word and balanced symbol equations for sodium hydroxide and hydrochloric acid?
Dalam Bahasa Indonesia:
Sodium Hydroxide = Natrium Hidroksida
dengan rumus molekul NaCl
Hydrochloric Acid = Asam Klorida
dengan rumus molekul HCl
Semoga Bermanfaat
#SemangatBelajar
7. When 10 cm³ of 0.5 mol dm3 sodium sulphate solution is added to excess lead (II) nitrate solution, a white precipitate is formed. Calculate the mass of precipitate formed.
Jawaban:
To solve this problem, we need to use the fact that a mole of a substance is a unit of mass equal to the atomic or molecular weight of that substance in grams.
We know that the concentration of the sodium sulphate solution is 0.5 mol/dm³, and that we have added 10 cm³ of the solution. Therefore, the number of moles of sodium sulphate in the solution is 0.5 x (10/1000) = 0.005 moles.
Sodium sulphate has a molecular weight of 142.04 g/mol, so the mass of sodium sulphate in the solution is 0.005 x 142.04 = 0.7102 g.
When sodium sulphate is added to lead (II) nitrate, a white precipitate of lead (II) sulphate is formed. The formula for lead (II) sulphate is PbSO4, and its molecular weight is 303.34 g/mol.
Thus, the mass of lead (II) sulphate precipitate formed is 0.005 x 303.34 = 1.5167 g.
Therefore, the mass of precipitate formed is 1.5167 grams.
8. Allah SWT created the earth with abundance of minerals. A sample mineral contained only chloride, iodide and nitrate anions. A titration was carried out to determine the chloride and iodide content. Standardized silver nitrate was used as titrant, and a silver wire immersed in the solution was used to monitor the solution’s electrochemical potential as the precipitates formed. The concentration of the standardized silver nitrate solution was 0,1 M. The burette initial reading was 1.35 mL, and the volumes at the two end points were 12.75 ml and 40.95 mL. Given that the original sample was 0.5 g, what is the percentage difference between iodide and chloride in the sample? (Ksp AgCl = 1,78 x 10-10, AgI = 9,8x10-17), (Molar mass, g.mol-1 for I=126,9, Cl=35,55) (Note: please write the answer IN NUMBER, WITHOUT writing the unit)
Jawaban:
ok
Penjelasan:
ngabisa bahasa Inggris
9. the reaction of potassium and silver with dilute acid
Penjelasan:
reaksi kalium dan perak dengan asam encer
10. Write the complete balanced equation for the reaction between iron (III) oxide (Fe2O3) and water (H2O). You do not need to make the subscripts smaller; just write them out as regular numbers. For example: Fe2O3
Fe2O3 + 3 H2O ---> 2 Fe(OH)3
11. IGCSE M/J 2018 The equation for the reaction between potassium carbonate and nitric acid is shown K₂CO₃ + 2HNO₃ => 2KNO₃ + H₂O + CO₂. Which volume of carbon dioxide is produced from 69 g of potassium carbonate ? A. 6 dm³ B. 12 dm³ C. 24 dm³ D. 48 dm³
Jawaban:
B. 12 dm³
Penjelasan:
jawabnya pakai bahasa indonesia ya
mol K₂CO₃ = gr/Mr = 69/138 = 0,5 mol
K₂CO₃ + 2HNO₃ => 2KNO₃ + H₂O + CO₂
0,5 mol -------------------------------------- 0,5 mol
"perb koefisien = perb mol"
menghitung volume bergantung keadaannya, bisa pada keadaan STP, RTP, pada PT terntentu, dan diukur pada gas lain. karena di soal tidak ada keterangan keadaannya, dan jika mengikuti angka" di opsi, kemungkinan keadaanya adalah RTP
V RTP CO₂ = mol × 24 = 0,5 × 24 = 12 L= 12 dm³
12. 2. A reaction between 70.0 g of copper(II) oxide and 50 mL of 2.0 M nitric acid produces copper(II) nitrate, Cu(NO3)2 and water. (a) Write the balanced chemical equation for the above reaction. (b) Determine the limiting reactant. (c) Calculate the mass of excess reactant after the reaction. (66.02 g) (d) Determine the percentage yield if the actual mass of copper(II) nitrate obtained from the reaction is 8.5 g (90.62%)
Jawaban:
a. The balanced chemical equation for the reaction above
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
b. he limiting reactant: nitric acid ([tex]HNO_{3}[/tex])
c. the mass of excess reactant after the reaction = 67,97 g
d. the percentage yield if the actual mass of copper(II) nitrate obtained from the reaction is 8.5 g = 50,47%
Penjelasan:
Persamaan reaksi dari reaksi tersebut adalah:
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
mol CuO = [tex]\frac{massa}{Mr}[/tex]
= [tex]\frac{70}{79,5}[/tex]
= 0,88 mol
mol [tex]HNO_{3}[/tex] = V x M
= 50 mL x 2 M
= 100 mmol = 0,1 mol
Pereaksi pembatas dapat ditentukan dengan membagi mol reaktan dengan keofisienya. Reaktan yang hasil baginya lebih kecil merupakan pereaksi pembatas.
[tex]\frac{mol CuO}{koef CuO}[/tex] = [tex]\frac{0,88}{1}[/tex] = 0,88
[tex]\frac{mol HNO_{3} }{koef HNO_{3} }[/tex] = [tex]\frac{0,1}{2}[/tex] = 0,05
Hasil bagi yang lebih kecil adalah [tex]HNO_{3}[/tex] jadi pereaksi pembatasnya adalah [tex]HNO_{3}[/tex]. Sehingga:
mol CuO yang bereaksi = [tex]\frac{koef CuO}{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
mol [tex]Cu(NO_{3})_{2}[/tex] hasil reaksi = [tex]\frac{koef Cu(NO_{3})_{2} }{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
mol [tex]H_{2}O[/tex] hasil reaksi = [tex]\frac{koef H_{2}O }{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
Awal : 0,88 mol 0,05 mol
Reaksi : 0,025 mol 0,05 mol 0,025 mol 0,025 mol
--------------------------------------------------------------------------------------------
Akhir : 0,855 mol - 0,025 mol 0,025 mol
Reaktan yang bersisa diakhir reaksi adalah CuO sebanyak 0,855 mol. Massa CuO = mol x Mr
= 0,855 x 79,5
= 67,97 g
[tex]Cu(NO_{3})_{2}[/tex] yang dihasilkan adalah 0,025 mol.
Massa [tex]Cu(NO_{3})_{2}[/tex] = mol x Mr
= 0,025 x 171,5
= 4,29 g
%[tex]Cu(NO_{3})_{2}[/tex] = [tex]\frac{4,29}{8,5}[/tex] x 100%
= 50,47%
Materi tentang pereaksi pembatas dapat disimak pada link:
https://brainly.co.id/tugas/40947892
#BelajarBersamaBrainly
13. hasil Kali kelarutan timbal (II)iodide adalah...
Pb2I ---> Pb2+ + I2- ksp = s.s Ksp = s2PbI2 ⇔ Pb2+ + 2I-
s s 2s
Ksp PbI2 = [Pb2+] [I-]²
Ksp PbI2 = [s] [2s]²
Ksp PbI2 = 4s³
Semoga Membantu
14. Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid !
Answer :Reaction Metal Metal =Zn(s) Hydrochloric acid solution =HCl(aq) Zinc Chloride =ZnCl2(aq) Hydrogen Gas =H2 (g) Zn(s)+HCl (aq) -->ZnCl2(aq)+H2 (g) EquateZn(s) +2HCl(aq)-->ZnCL2 (aq) +H2 (g)
15. Mengapa sumber manusia dikelompokkan sebagai lead indicator dalam kategori balanced scorecard dari kaplan dan norton.
Jawaban:
Karena Sumber Daya Manusia adalah penentu keberhasilan visi misi perusahaan
Penjelasan:
Walaupun visi misi suatu perusahaan bagus serta dilengkapi dengan peralatan canggih namun jika tidak memiliki SDM yang memadai mustahil tujuan perusahaan dapat tercapai. Oleh karena itu sumber manusia dikelompokkan sebagai lead indicator dalam kategori balanced scorecard dari kaplan dan norton.
16. in which compounds are pairs of electrons shared between atoms? 1) methane 2) potassium iodide 3) sodium chloride a. 1 only, b. 2 only, c. 1 and 3, d. 1, 2 and 3
1 Methane
semoga benar adanya
17. Magnesium Sulfate could be made in the laboratory by neutralising a base, Magnesium Oxide, with an acid. What is the acid and write a balanced equation for the reaction.
The acid is sulphuric acid (H2SO4)
The reaction is:
[tex] MgO + H_2SO_4 => MgSO_4 + H_2O [/tex]H₂SO₄ (sulfuric acid)
Balanced equation of the reaction
[tex]MgO_{(s)} + H_2SO_4_{(aq)} \rightarrow MgSO_4_{(aq)} + H_2O_{(l)} [/tex]
18. when lead is heated in oxygen. lead(II)oxide id formed write a word equation for this reaction
balanced equation
2Pb + O₂ → 2PbO2Pb + O₂ → 2 PbO
2Pb(s) + O2(g) →2PbO(s)
19. To lead a well balanced life, you need to have other interest _________ studying. * 4 poin
Jawaban:
than just
Penjelasan:
semoga membantu dan maaf kalo salah
20. ammonia nitrate is prepared commericially by passing ammonia gas througs a solution of nitrate acid .write down the balance equation
[STOICHIOMETRY | X SHS]
Ammonium Nitrate : NH₄NO₃
Ammonia : NH₃
Nitrate acid : HNO₃
NH₃ + HNO₃ --> NH₄NO₃ (balanced)
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