The guy cables AB and AC are attached to the top of the transmission tower. The tension in cable AC is 8 kN. Determine the required tension T in cable AB such that the net effect of the two cable tensions is a downward force at point A. determine the magnitude R of this downward force!
1. The guy cables AB and AC are attached to the top of the transmission tower. The tension in cable AC is 8 kN. Determine the required tension T in cable AB such that the net effect of the two cable tensions is a downward force at point A. determine the magnitude R of this downward force!
Hope it helps, and stay motivated
2. 2/85 While sliding a desk toward the doorway, three stu- dents exert the forces shown in the overhead view. Determine the equivalent force-couple system at point A. Then determine the equation of the line of action of the resultant force. Ans. R = 45i - 150 lb, MA = -1650k lb-in. 1 110 3 3 + 60" 25 lb 15 lb 30" 20 lb
Jawaban:
ada tabel nya ngga ? biar gampang
3. Determine the dimension of the following physical quantities: a. momentum b. power (P) c. accelaration (a) d. force e. density (p)
a. Momentum, p = m.v (kg.m/s)
b. Power, P = W/t (Joule/s) or (Nm/s) or Watt (W)
c. Acceleration, a = ΔV/Δs (m/s2)
d. Force, F = m.a (kg.m/s2) or Newton (N)
e. Density, ρ = m/v (kg/m3)
4. 750-gram water at 15°C mixed with 1kg water at 95°C. Determine the final temperature of the mixture!
Jawaban:
750 gr = 0,75 kg
Q = m.c.∆T
both of them are water so u can ignore c
0,75 . c . ( T-15 ) = 1 . c . ( 95-T )
0,75T - 11,25 = 95 - T
1,75 T = 95 + 11,25
T = 106,25 / 1,75
T = 60,714285714285 °C
T = 60,7 ° C
5. clues1. gravitational force can act at a____from am object.2. the force of______bettween object and the earth is called gravitational force.3.the______of an object is the amount of matter the object jas.4.the force that pulls all object_____ is caleed gravitational force.5.the______of an object is gravitational force between the object and the earth
Jawaban:
gravitasi
Penjelasan:
karena gerak gravitasi yang bergerak
6. A wooden log having a mass of 500 gram is shifting horizontally at a rapidity of 6 m/s; given a force that moves in an opposite direction, contrary to the direction of the log's direction that makes its acceleration turns to 2 m/s. Please determine the magnitude of the work done by the force? tolong, :(
Pertanyaan (Jika di translate)
Sebuah kayu yang memiliki massa 500 gram bergeser secara horizontal dengan kecepatan 6 m / s; diberikan gaya yang bergerak dalam arah yang berlawanan, dengan arah log yang membuat kecepatannya berubah menjadi 2 m / s. Tentukan besarnya kekuatan yang dihasilkan oleh tekanan
Jawaban dengan langkah-langkah:
M = 500 g = 0,5 kg
V₁ = 6 m/s
V₂ = 2 m/s
Ditanya: W =...?
W = Ek = 1/2 mv₁² - 1/2 mv₂²
= 1/2 x 0,5 x 6² - 1/2 x 0,5 x 2²
= 9 - 1
= 8 Joule
7. Look at the pictures and determine when it happened!
Jawaban:
Lihatlah gambar-gambarnya dan tentukan kapan itu terjadi!
Penjelasan:
Semoga jawabanmu benar.
8. Analyze the types of password cracker attacks to determine which scenario best describes a brute force attack !
Jawaban: An attacker attempts every possible combination in the key space in order to derive a plaintext password from a hash
9. Which of the following is a contact force?a. Electrostatic forcec. Gravitational forceb. Frictional forced. Magnetic force
Jawaban:
A. Electrostatic
Penjelasan:
Kayak ny menurut saya
10. How to determine the force in each member of the truss.Then state if the members are in tension or compression
Jawaban:
Bagaimana menentukan kekuatan di setiap anggota rangka. Kemudian nyatakan apakah anggota dalam ketegangan atau kompresi
11. Determine the gravitational force attractional between the earth ( m=5,98 X 10^24 kg) and a 66,7 kg satelite is flying on the earth surface at distance of 6.67 X 10^6 m from earth center
GRAVITATION
F = ___?
M = 5.98×10^24 kg
m = 66.7 kg
r = 6.67×10^6 m
F = G M m / r²
F = 6.67×10^−11× 5.98×10^24 × 66.7)/(6.67×10^6)^2
F = 598 N ✔️Dicari Fgravitasi
Fgravitasi = G.mbumi.msatelit/r²
G = 6,67x10^-11
Mbumi = 5,98x10^24
Msatelit = 66,7 kg
Maka
Fgravitasi = 6,67x10^-11 . 5,98x 10^24 . 66,7/ 6,67 x 10^6 . 6,67 x 10 ^6
Tinggal dicoret yah, jadinya
F gravitasi = 5,98x10^24. 10. 10^-23
F gravitasi = 598N
Semoga membantu:)
12. Electrostatic force between two charged object is F. The distance between them is 10 mm. If the distance between them becomes 40 mm, determine the electrostatic force between them!
Answer: F1/16 = F/16
Description:
Electrostatic force = F
F = (k.q1.q2)/r²
First condition distance between 2 charge object = 10mm = 0,01 m
Second condition distance between 2 charge object = 40mm = 0,04 m
For first condition
F1 = F = k.q1.q2/(0.01)² = kq1.q2/(0.0001)
F1 = F = 10⁴.k.q1.q2
For second condition
F2 = k.q1.q2/(0.04)² = k.q1.q2/0.0016
F2 = 10⁴k.q1.q2/16
10⁴.k.q1.q2 = F1
Then
F2 = F1/16
F2 = F/16
So the electrostatic force in 40mm is F1/16 = F/16
13. A girl is dragging a sled of mass 20kg up a slope at angle 14° to the horizontal. She pulls at an angle of theta above the slope with a force 70 N. She maintains a constant speed despite friction of 10N parallel to the slope. Find theta and the normal contact force.
Jawaban:
is named after listening and the bear
14. Q is the midpoint of the straight line which joined point P (-3, 4) and point R (7, 10). Determine the y-coordinate of point Q. *
HALO SAYA ORANG BAARU DENGAN PARAGRAF tersebut 1+1=9
15. The elements of a heavy-duty fluid valve are shown in the figure. When the member OB rotates clockwise about the fixed pivot O under the action of the force P, the element S slides freely upward in its slot, releasing the flow. If an internal tensional spring exerts a moment M – 20 N.m as shown, determine the force p required to open the valve. Neglect all friction
the elements of a heavy-duty fluid
16. determine the distance from point e tool in action cupu abcd efgh
Jawaban:
ijklmnopkrsnakzbsjam
17. . In a game of tug-of-war, both sides aren’t moving because each team have the same equal strength. What type of force is this? (10 Points) Balanced force Normal force Unbalanced force Spring Force
Jawaban: r u kelly from 6c
18. Questions 1. From which hole does the water shoot out with the greatesest force? How can you tell? 2. From which hole does the water shoot out with the least force? 3. The force with which water shoots out from a hole increases as the liquid pressure acting on the water at that point increases. At which hole is the liquid pressure (a) the greatest? ...(b) the least? Conclusion Liquid pressure is greater at... than at... and.... As depth increases, liquid pressure...
Jawaban:
Penjelasan:
The greatest force is in the small cross-sectional area, while the smallest force is in the large cross-sectional area
it can be seen in the equation F = P/A
I don't give you a conclusion because maybe that question have a picture
19. A man applies a force of 50 N at an angle of60° to the horizontal. The component of thisforce in the horizontal direction is....
F = 50 N
[tex] \displaystyle \theta[/tex] = 60°
[tex] \displaystyle F_x = \dots?[/tex]
Answer:[tex] \displaystyle \begin{aligned} F_x &= F\cos(\theta) \\ &= 50\cdot\cos(60\degree) \\ &= 50\cdot\frac{1}{2} \\ &= \boxed{\bold{25\:N } } \end{aligned}[/tex]
20. The electrostatic force between two charged object is 0,8 N when the distance between them is 3,5 mm. Determine the electrostatic force if the distance between them becomes 7 mm!
Jawaban:
0,2 N
Penjelasan:
F = k q1 q2 / r²
F1/F2 = r2²/r1²
0,8/F2 = 7²/3,5² = 4
F2= 0,8/4 = 0,2 N
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