9x9:8x83x2berapa jawaban yang aku tulis
1. 9x9:8x83x2berapa jawaban yang aku tulis
Jawaban:
9×9=81
8×8=64
3×2=6
Penjelasan dengan langkah-langkah:
semoga membantu
2. 8x8= 9x9= 10x9= 19x7= 20x5=
Jawaban:
8×8 = 64
9×9= 81
10×9= 90
19×7= 133
20×5= 100
Penjelasan dengan langkah-langkah:
Perkalian adalah penjumlahan berulang-ulang.
Contohnya:
8×8= 8+8+8+8+8+8+8+8 = 64
Jawab:
1. 64
2. 81
3. 90
4. 133
5. 100
Penjelasan dengan langkah-langkah:
1. 8 × 4 = 32 + 32 = 64
2. 9 × 3 = 27 + 27 + 27 = 81
3. 10 × 3 = 30 + 30 + 30 = 90
4. 19 × 2 = 38 + 38 + 38 = 112 +21 = 133
5. 20 × 2 = 40 + 40 = 80 + 20 = 100
3. Quiz10x109x98x8366+458
Jawaban:
10×10=100
9×9=81
8×8=64
366+458=824
Penjelasan dengan langkah-langkah:
semoga membantumakasih poinnya
4. dijawab pls 1x1 2x2 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x1
1x1=1
2x2=4
3x3=9
4x4=16
5x5=25
6x6=36
7x7=49
8x8=64
9x9=81
10x1=10
[tex] {1}^{2} = 1 \\ {2}^{2} = 4 \\ {3}^{2} = 9 \\ {4}^{2} = 16 \\ {5}^{2} = 25 \\ {6}^{2} = 36 \\ {7}^{2} = 49 \\ {8}^{2} = 64 \\ {9}^{2} = 81 \\ {10}^{2} = 100[/tex]
5. tolong1x12x23x34x455x56x67x78x89x910x10
Jawaban:
1 × 1 = 1
2 × 2 = 4
3 × 3 = 9
4 × 4 = 16
55 × 5 = 275
6 × 6 = 36
7 × 7 = 49
8 × 8 = 64
9 × 9 = 81
10 × 10 = 100
1 × 1 = 1
2 × 2 = 4
3 × 3 = 9
4 × 4 = 16
55 × 5 = 275
6 × 6 = 36
7 × 7 = 49
8 × 8 = 64
9 × 9 = 81
10 × 10 = 100
Terimakasih
6. which thing is like cube? it is
Jawaban:
itu di translate atau langsung jawabannya ☺️
7. Hasil dari 362+27x15
362+(27x15)
=362+405
=767
operasi hitung dalam matematika biasakan untuk memulai pengkalian dari pada penjumlahan362+27=389
389×15=767
8. Cube A has a volume of 4913 cm^3 and cube B has a volume of 2744 cm^3. How much wider is cube A than cube B
Jawaban:
cube A
4913^3=S^3
S=17
cube B
2744^3=S^3
S=14
✨cube A is 3cm more than cube B
9. The face area of a cube is 484 cm2. The surface area of cube is ….
Jawaban:
2904cm²
Penjelasan dengan langkah-langkah:
surface area = 6 × face area
= 6 × 484
= 2904cm²
10. Dharma has a box shaped like a cube which has edge of 20 cm. Dharma's cube volume is…cm3
V= 20x20x20
= 8000 cm^3
11. 1x1 2x2 3x3 4x4 5x5 6x6 7x7 8x8 9x9 100x10
Penjelasan dengan langkah-langkah:
jawaban terlampir .....
12. k is a non-zero whole number. Given that 6 * 54 * k is a perfect cube, write down the smallest value of k.
Karena 6² dan 3² adalah bilangan kuadrat sempurna, maka 6² * 3² juga merupakan bilangan kuadrat sempurna. Jadi, nilai k terkecil agar 6*54*k merupakan bilangan kuadrat sempurna adalah k = 1.
Penjelasan dengan langkah-langkah:
Diketahui:
K adalah bilangan bulat tak nol. Diberikan 6*54*k adalah bilangan kudrat sempurna.
Ditanya:
Tuliskan nilai k terkecil !
Jawab:
Diketahui bahwa k adalah bilangan bulat tak nol.
Perhatikan bahwa
6*54*k = 6*6*9*k = 6² * 3² * k
Karena 6² dan 3² adalah bilangan kuadrat sempurna, maka 6² * 3² juga merupakan bilangan kuadrat sempurna. Jadi, nilai k terkecil agar 6*54*k merupakan bilangan kuadrat sempurna adalah k = 1.
Pelajari lebih lanjut
Pelajari lebih lanjut tentang bilangan kuadrat sempurna pada
https://brainly.co.id/tugas/14004
#BelajarBersamaBrainly#SPJ1
13. I had a cube and every side it had is 20cm what is the volume of that cube?
Solution :
Cube side => 20 cm
Volume cube : side × side × side
Volume cube : 20 cm × 20 cm × 20 cm
Volume cube : 400 cm² × 20 cm
Volume cube : 8.000cm³
Conclusion:Volume of that cube 8.000cm³
14. The volume of Cube A is 64cm3. The length of cube B is twice the length of cube A. Find the volume of cube B. piw kka can you help this?
Soal dapat diterjemahkan menjadi :
Volume Kubus A adalah 64 cm³. Panjang rusuk kubus B adalah dua kali panjang rusuk kubus A, maka volume kubus B adalah [tex]512[/tex] cm³
Diketahui :Kubus A dan Kubus B
[tex]\text {V}_\text A[/tex] = 64 cm³
[tex]\text {s}_\text B[/tex] = [tex]2 \times \text {s}_\text A[/tex]
[tex]\text {s}_\text A[/tex] = rusuk kubus A
[tex]\text {s}_\text B[/tex] = rusuk kubus B
Ditanyakan :Volume kubus B
Jawab :Rumus volume kubus adalah [tex]\boxed {\text V = \text s^3}[/tex], untuk s adalah panjang rusuk kubus
Maka
Cara 1Volume kubus A
[tex]\text {V}_\text A[/tex] = 64 cm³
⇔ [tex]\text {V}_\text A[/tex] = [tex](\text {s}_\text A)^3[/tex] = 64 cm³
Volume kubus B
[tex]\text {V}_\text B[/tex] = [tex](\text {s}_\text B)^3[/tex], dengan syarat [tex]\text {s}_\text B[/tex] = [tex]2 \times \text {s}_\text A[/tex], didapat :
⇔ [tex]\text {V}_\text B[/tex] = [tex](2 \times \text {s}_\text A)^3[/tex]
⇔ [tex]\text {V}_\text B[/tex] = [tex]2^3 (\text {s}_\text A)^3[/tex]
⇔ [tex]\text {V}_\text B[/tex] = [tex]8 \times 64[/tex]
⇔ [tex]\text {V}_\text B[/tex] = [tex]512[/tex] cm³
∴ Jadi volume kubus B adalah [tex]512[/tex] cm³
Cara 2[tex]\text {V}_\text A[/tex] = 64 cm³
⇔ [tex]64[/tex] = [tex](\text {s}_\text A)^3[/tex]
⇔ [tex](\text {s}_\text A)^3[/tex] = [tex]64[/tex]
⇔ [tex]\text {s}_\text A[/tex] = [tex]\sqrt[3]{64}[/tex]
⇔ [tex]\text {s}_\text A[/tex] = [tex]\sqrt[3]{64}[/tex]
⇔ [tex]\text {s}_\text A[/tex] = [tex]4[/tex] cm
Panjang rusuk kubus A = 4 cm
Panjang rusuk kubus B adalah : [tex]\text {s}_\text B[/tex] = [tex]2 \times \text {s}_\text A[/tex], maka
[tex]\text {s}_\text B[/tex] = [tex]2 \times \text {s}_\text A[/tex]
⇔ [tex]\text {s}_\text B[/tex] = [tex]2 \times 4[/tex]
⇔ [tex]\text {s}_\text B[/tex] = [tex]8[/tex] cm
Volume kubus B,
[tex]\text {V}_\text B[/tex] = [tex]( \text {s}_\text B)^3[/tex]
⇔ [tex]\text {V}_\text B[/tex] = [tex](8)^3[/tex]
⇔ [tex]\text {V}_\text B[/tex] = [tex]512[/tex] cm³
∴ Jadi volume kubus B adalah [tex]512[/tex] cm³
15. The following net is folded into cube. Write down the letter on the cube which is opposite the shaded face.(A, B, C, D or E)
Jawaban:
answer : A
Penjelasan dengan langkah-langkah:
sorry if wrong
16. Find the smallest integer a such that 945a is a perfect cube.
There is no smallest integer [tex]a[/tex] such that [tex]945a[/tex] is a perfect cube.
However, if [tex]a[/tex] or the perfect cube is a positive integer, the smallest integer a such that [tex]945a[/tex] is a perfect cube is 1225.
Let [tex]b[/tex] be the root of the perfect cube which is the value of [tex]945a[/tex]. Thus,
[tex]\large\text{$\begin{aligned}b^3=945a\end{aligned}$}[/tex]
By prime factorization, we get:
[tex]\large\text{$\begin{aligned}b^3&=3\cdot315\cdot a\\&=3\cdot3\cdot105\cdot a\\&=3\cdot3\cdot3\cdot35\cdot a\\&=3^3\cdot5\cdot7\cdot a\\\end{aligned}$}[/tex]
The integer [tex]a[/tex] should be in the form of [tex]{}\pm 35^{(3k-1)}[/tex], [tex]k=1,2,3,{\dots}[/tex]. Unlike perfect squares, perfect cubes could be negative. Hence, temporary solution we can get is:
[tex]\large\text{$\begin{aligned}&a=-\left(35^{(3k-1)}\right )\\&\quad k=1,2,3,{\dots}\end{aligned}$}[/tex]
The larger the [tex]k[/tex] is, the smaller the [tex]a[/tex] will be.
THEREFORE, there is no smallest integer [tex]a[/tex] such that [tex]945a[/tex] is a perfect cube.
However, if [tex]a[/tex] or the perfect cube is a positive integer, the smallest integer [tex]a[/tex] such that [tex]945a[/tex] is a perfect cube is:
[tex]\large\text{$\begin{aligned}a&=35^{(3\cdot1\:-\:1)}\\&=35^2\\&=\bf1225\end{aligned}$}[/tex]
[tex]\blacksquare[/tex]
17. there is a cube with a length of 6 m filled with water with a hole in the side which is 2 m higher than the base of the cube (the hole is a square) and there is another cube with a length of 5m beside the hole, how many m3 of water will be in the first cube, and the m3 of water in the second cube
Jawaban:
ada kubus dengan panjang 6 m diisi air dengan lubang di sisi yang lebih tinggi 2 m dari alas kubus (lubangnya persegi) dan ada kubus lain dengan panjang 5 m di sampingnya
18. The surface area of a cube is 864 cm2. The volume of the cube is …
Let the edge of the cube be 1 cm.
Total surface area of the cube = 864 cm²
6L² = 864 cm²
I² = 864/6 = 144
I =
[tex] \sqrt{144} [/tex]
= 12 cm
Volume of the cube = I³= (12)³ = 1728 cm³
Thus, the volume of the cube is 1728 cm³
19. mabar roblox nanti yuk namaku realgoodguy01 1x1= 2x2= 3x3= 4x4= 5x5= 6x6= 7x7= 8x8= 9x9= 10x10= 11x11= 12x12=
1
4
9
16
25
36
49
64
81
100
121
244
Jawaban:
1x1=1
2x2=4
3x3=9
4x4=16
5x5=25
6x6=36
7x7=49
8x8=64
9x9=81
10x10=100
11x11=121
12x12=144
Penjelasan dengan langkah-langkah:
perkalian berulang 2 kali dengan angka yang sama bisa juga disebut dengan pangkat 2 (a²)
perkalian berulang 2 kali dengan angka yang sama bisa juga disebut dengan pangkat 2 (a²)contoh:
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=47
8²=64
9²=81
10²=100
11²=121
12²=144
20. 1x1? 2x2? 3x3? 4x4? 5x5? 6x6? 7x7? 8x8? 9x9? 10x10?
1
4
9
16
25
36
49
64
81
100
Itu jawabannya1×1=1
2×2=4
3×3=9
4×4=16
5×5=25
6×6=36
7×7=49
8×8=64
9×9=81
10×10=100
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